4a^2-16a+16=3a+4

Solution for 4a^2-16a+16=3a+4 equation:

4a^2-16a+16=3a+4

We move all terms to the left:

4a^2-16a+16-(3a+4)=0

We get rid of parentheses

4a^2-16a-3a-4+16=0

We add all the numbers together, and all the variables

4a^2-19a+12=0

a = 4; b = -19; c = +12;
Δ = b2-4ac
Δ = -192-4·4·12
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-13}{2*4}=\frac{6}{8}
=3/4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+13}{2*4}=\frac{32}{8}
=4
$